| SAN
LUIS, Argentina, Oct 15, 2005: With the title having been
settled with a round to spare, the game between Viswanathan
Anand and Peter Svidler was the focus of the 14th and final
round of the FIDE World Chess Championships at San Luis. As
the Svidler-Anand game ended in a draw, Anand by virtue of
the tie-break system used in the tournament, was adjudged
second and Svidler third.
The
winner was Veselin Topalov, whose draw against Judit Polgar
left him 1.5 points ahead of the field, with a 2890 performance,
that should see him cross 2800 points in the next rating list.
Anand also has a plus rating finish and could come to about
2793.
The
first tiebreak criteria was the direct results between the
two players, which in the case of Anand and Svidler was two
draws. The second was the number of wins, and with Anand having
five and Svidler four the Indian former world champion was
second.
Topalov,
who did not win a single game in the second half was happy
with an 18-move draw with Judit Polgar, who had a poor tournament.
The game was Queen’s Indian and it ended a great tournament
for the Bulgarian.
Svidler
needed to win against Anand due to his inferior tie-break.
But he found breaking Anand’s Petroff Defence extremely
difficult. He tried castling queenside in an attempt to inject
a bit of life into proceedings. But Anand, with black, had
no problems dealing with it. In the end, the players agreed
to a 19-move draw that left Anand runner-up and Svidler third.
Alexander Morozevich drew with Michael Adams
in 54 moves of a Ruy Lopez.
Peter
Leko had an edge in the White side of a Sicilian Paulsen against
Rustam Kasimjanov, and the Hungarian wore down Kasim in 54
moves for the only win in the final round.
Results
of Round 14: Leko beat Kasimjanov; Topalov drew with Polgar;
Svidler drew with Anand; Morozevich drew with Adams
Final Standings: 1. Topalov 10.0; 2. Anand 8.5; 3. Svidler
8.5; 4. Morozevich 7.0; 5. Leko 6.5; 6. Kasimjanov 5.5; 7.
Adams 5.5; 8. Polgar 4.5
Svidler
v Anand
1.
e4 e5 2. Nf3 Nf6 3. Nxe5 d6 4. Nf3 Nxe4 5. Nc3 Nxc3 6. dxc3
Be7 7. Be3 Nc6 8. Qd2 O-O 9. O-O-O Ne5 10. Kb1 Re8 11. Nd4
a6 12. f4 Ng4 13. Bd3 d5 14. Rhe1 Bh4 15. g3 Nxe3 16. Rxe3
Rxe3 17. Qxe3 Bf6 18. Nf3 Qe7 19. Qxe7 1/2-1/2
|
